[LeetCode]Find Pivot Index

题目描述：

LeetCode 724. Find Pivot Index

Given an array of integers nums, write a method that returns the "pivot" index of this array.

We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the index.

If no such index exists, we should return -1. If there are multiple pivot indexes, you should return the left-most pivot index.

Example 1:

Input:
nums = [1, 7, 3, 6, 5, 6]Output: 3Explanation:
The sum of the numbers to the left of index 3 (nums[3] = 6) is equal to the sum of numbers to the right of index 3.
Also, 3 is the first index where this occurs.

Example 2:

Input:
nums = [1, 2, 3]Output: -1Explanation:
There is no index that satisfies the conditions in the problem statement.

Note:

• The length of nums will be in the range [0, 10000].
• Each element nums[i] will be an integer in the range [-1000, 1000].

题目大意：

给定数组，寻找枢轴下标，使得其左侧的值之和等于其右侧的值之和。

若不存在，则返回-1。

解题思路：

求数组的和，然后一趟遍历即可。

Python代码：

class Solution(object):
    def pivotIndex(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        sums = sum(nums)
        total = 0
        for x, n in enumerate(nums):
            if sums - n == 2 * total: return x
            total += n
        return -1